0.00/0.00	MAYBE
0.00/0.00	
0.00/0.00	
0.00/0.00	Succeeded in reading "/export/starexec/sandbox2/benchmark/theBenchmark.trs".
0.00/0.00	    (CONDITIONTYPE ORIENTED)
0.00/0.00	    (VAR x y z w)
0.00/0.00	    (RULES
0.00/0.00	      div(z,y) -> x | mul(x,y) == z, gt(y,0) == tt
0.00/0.00	      mul(x,0) -> 0
0.00/0.00	      mul(0,y) -> 0
0.00/0.00	      mul(s(x),s(y)) -> s(z) | mul(x,s(y)) == w, add(w,y) == z
0.00/0.00	      gt(0,y) -> ff
0.00/0.00	      gt(s(x),0) -> tt
0.00/0.00	      gt(s(x),s(y)) -> z | gt(x,y) == z
0.00/0.00	    )
0.00/0.00	    (COMMENT doi:10.1016/j.tcs.2012.09.005 [72] Example 4 submitted by: Thomas Sternagel and Aart Middeldorp)
0.00/0.00	
0.00/0.00	No "->="-rules.
0.00/0.00	
0.00/0.00	Decomposed conditions if possible.
0.00/0.00	    (CONDITIONTYPE ORIENTED)
0.00/0.00	    (VAR x y z w)
0.00/0.00	    (RULES
0.00/0.00	      div(z,y) -> x | mul(x,y) == z, gt(y,0) == tt
0.00/0.00	      mul(x,0) -> 0
0.00/0.00	      mul(0,y) -> 0
0.00/0.00	      mul(s(x),s(y)) -> s(z) | mul(x,s(y)) == w, add(w,y) == z
0.00/0.00	      gt(0,y) -> ff
0.00/0.00	      gt(s(x),0) -> tt
0.00/0.00	      gt(s(x),s(y)) -> z | gt(x,y) == z
0.00/0.00	    )
0.00/0.00	    (COMMENT doi:10.1016/j.tcs.2012.09.005 [72] Example 4 submitted by: Thomas Sternagel and Aart Middeldorp)
0.00/0.00	
0.00/0.00	Removed infeasible rules as much as possible.
0.00/0.00	    (CONDITIONTYPE ORIENTED)
0.00/0.00	    (VAR x y z w)
0.00/0.00	    (RULES
0.00/0.00	      div(z,y) -> x | mul(x,y) == z, gt(y,0) == tt
0.00/0.00	      mul(x,0) -> 0
0.00/0.00	      mul(0,y) -> 0
0.00/0.00	      mul(s(x),s(y)) -> s(z) | mul(x,s(y)) == w, add(w,y) == z
0.00/0.00	      gt(0,y) -> ff
0.00/0.00	      gt(s(x),0) -> tt
0.00/0.00	      gt(s(x),s(y)) -> z | gt(x,y) == z
0.00/0.00	    )
0.00/0.00	    (COMMENT doi:10.1016/j.tcs.2012.09.005 [72] Example 4 submitted by: Thomas Sternagel and Aart Middeldorp)
0.00/0.00	
0.00/0.00	Try to disprove confluence of the following (C)TRS:
0.00/0.00	    (CONDITIONTYPE ORIENTED)
0.00/0.00	    (VAR x y z w)
0.00/0.00	    (RULES
0.00/0.00	      div(z,y) -> x | mul(x,y) == z, gt(y,0) == tt
0.00/0.00	      mul(x,0) -> 0
0.00/0.00	      mul(0,y) -> 0
0.00/0.00	      mul(s(x),s(y)) -> s(z) | mul(x,s(y)) == w, add(w,y) == z
0.00/0.00	      gt(0,y) -> ff
0.00/0.00	      gt(s(x),0) -> tt
0.00/0.00	      gt(s(x),s(y)) -> z | gt(x,y) == z
0.00/0.00	    )
0.00/0.00	    (COMMENT doi:10.1016/j.tcs.2012.09.005 [72] Example 4 submitted by: Thomas Sternagel and Aart Middeldorp)
0.00/0.00	
0.00/0.00	Failed either to apply SR and U for normal 1CTRSs to the above CTRS or to prove confluence of any converted TRSs.
0.00/0.00	
0.00/0.00	Try to apply SR and U for 3DCTRSs to the above CTRS.
0.00/0.00	EOF