Problem:
 f(x,y) -> f(g(x),g(x))
 g(x) -> h(x)
 F(g(x),x) -> F(x,g(x))
 F(h(x),x) -> F(x,h(x))

Proof:
 sorted: (order)
 0:f(x,y) -> f(g(x),g(x))
   g(x) -> h(x)
 1:g(x) -> h(x)
   F(g(x),x) -> F(x,g(x))
   F(h(x),x) -> F(x,h(x))
 -----
 sorts
   [1>3, 2>4, 3>4]
 sort attachment (strict)
   f : 4 x 3 -> 1
   g : 4 -> 4
   h : 4 -> 4
   F : 4 x 4 -> 2
 -----
 0:f(x,y) -> f(g(x),g(x))
   g(x) -> h(x)
   Church Rosser Transformation Processor:
    
    strict:
     f(x,y) -> f(g(x),g(x))
     g(x) -> h(x)
    weak:
     
    critical peaks: 0
    Closedness Processor (*parallel*):
     
     strict:
      
     weak:
      
     Qed
 
 
 1:g(x) -> h(x)
   F(g(x),x) -> F(x,g(x))
   F(h(x),x) -> F(x,h(x))
   Church Rosser Transformation Processor (kb):
    g(x) -> h(x)
    F(g(x),x) -> F(x,g(x))
    F(h(x),x) -> F(x,h(x))
    critical peaks: joinable
    Matrix Interpretation Processor: dim=1
     
     interpretation:
      [F](x0, x1) = 2x0 + x1,
      
      [h](x0) = 2x0 + 2,
      
      [g](x0) = 4x0 + 4
     orientation:
      g(x) = 4x + 4 >= 2x + 2 = h(x)
      
      F(g(x),x) = 9x + 8 >= 6x + 4 = F(x,g(x))
      
      F(h(x),x) = 5x + 4 >= 4x + 2 = F(x,h(x))
     problem:
      
     Qed